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Professional JavaScript

Inheritance via a Shared Class Object

The simplest form of inheritance in JavaScript is for the object instance for the derived class to collect the information it inherits from the class definition object for its base class. Therefore this is a case of mixing up instance and class objects.

function Polygon() { this.edges = 8; // octogons are the default this.regular = false; // sides needn't be all the same this.area = new Function (...) // some hard mathematics } function Rectangle(top_len, side_len) { this.edges = 4; this.top = top_len; this.side = side_len; this.area = new Function("return this.top*this.sides"); } Rectangle.prototype = new Polygon;

This example has two object constructors: the two functions. Since functions are objects in JavaScript, there are two new objects as well. There is also a third new object. It has been added to the Rectangle function object's prototype chain in the last line, and that is the only place it is accessible. That object can be thought of as a class definition object, because it is only really used at object creation time, and there is only ever one of it.

To create a new Rectangle, use this code:

var box = new Rectangle(8,3);

Afterwards the object's properties are:

box.edges = 4 // overrides Polygon box.top = 8 box.side = 3 box.area = Function("return this.top*this.sides"); box.regular=false // from Polygon

The benefits of this approach are:

  • Simplicity - inheritance is achieved with the single extra statement Rectangle.prototype = ..
  • Properties in the derived objects correctly override base object properties.
  • Information in the base object is not duplicated; it is looked up via the prototype chain.
  • If you modify the base object, which is acting like a class definition, then all of the derived objects will see the change.
  • Any amount of inheritance hierarchy is possible – Square objects could have Rectangles in their prototype chain and they would benefit from the Polygon class object instance as well.

However, this approach does have drawbacks. The problems mostly revolve around the fact that there is only one prototype chain for the Rectangle constructor, and it is shared between all Rectangle objects that are created. So any Rectangle object that modifies properties of the base class changes them for all Rectangle objects.

  • Modifying the base class object's properties doesn't just affect the current object; it affects all objects of this type that are hanging around.
  • The base class object's constructor (Polygon() in this case) can't have any arguments; or at least it must be able to survive without being passed any arguments.

You can work around the first problem by overriding all the base class objects properties in the derived instance object constructor (Rectangle). However, if you do that, overriding everything, one wonders why bother use inheritance at all – you might as well just have a separate object type.

Sometimes you do want properties in the base class to be updated by every derived instance ('static class variables'). Here's an example:

function Counter() { this.total=0; } function StockItem() { this.total++; } StockItem.prototype = new Counter; var biscuits = new StockItem; // total = 1 var coffee = new StockItem; // total = 2

Every object contributes something to the shared property. In the example above, this property is a total of the objects currently existing (this simple example doesn't correctly decrease the total if objects go away).

Finally, if you can avoid changing any state in the base class object, then the approach we've outlined here can still be quite useful. You could put a store of constant data and methods in it that will be usable by all derived instance objects. The methods in the base class object can refer to properties in derived instances as well. Here's an example:

function Base(v) { if (arguments.length != 0) this.value = v; this.double_up = new Function ("this.value*=2;") } function Derived(v) {this.value = v;} Derived.prototype = new Base; var obj = new Derived(5); obj.double_up(); // this.value = 10

Notice how in this example the base class object uses, but may never define the value property. In that case, the derived instance object's value property will be doubled. The 'if' condition in the base class object is only true if the Base() function is used as a simple constructor, not when inheritance is at work. For C++ and Java experts: this mechanism works well for abstract base classes.

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Copyright 1999 (1st Edition) and 2001 (2nd Edition) Wrox Press Ltd. and

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Created: February 12, 2001
Revised: February 12, 2001


URL: http://webreference.com/programming/javascript/professional/chap3/